Question

When one mole of cocl3.5nh3 was treated with excess of silver nitrate solution, 2 mol of agcl was precipitated. The formula of the compound?

Answer 1

Answer: b) [Co(NH3)5Cl]Cl2

Explanation : Since 2 moles of AgCl was precipitated out, the 2 moles of Cl- should be available as the ionizable ion outside the coordination sphere. In this way only, Cl- from the coordination compound would be available for precipitation.

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Answer 2

The formula of the compound is  [Co(NH3)5Cl]Cl2

Explanation:

• Since 2 moles of AgCl was precipitated out.
• Therefore the 2 moles of Cl- should be available as the ionisable ion outside the coordination sphere.
• In this way only, Cl- from the coordination compound would be available for precipitation.
• Thus the formula is [Co(NH3)5Cl]Cl2

Hence the formula of the compound is  [Co(NH3)5Cl]Cl2

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