When one mole of ethyl alcohol is mixed with one mole of acetic acid at room temperature,the equilibrium mixture contains 2/3 mole of ethyl acetate and 2/3 mole of water.What is the Kc for the reaction?
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Let us assume that the one mole of CH
3
COOH and C
2
H
5
O
5
are present and
3
2
rd of CH
3
COOH and C
2
H
5
OH is consumed . It gives CH
3
COOH
left=1−
3
2
C
2
H
5
OH=1−
3
2
Hence the number of moles of water and CH
3
COOC
2
H
5
are
3
2
each
K
a
=
(
3
1
×
3
1
)
(
3
2
×
3
2
)
=4
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