Question

when one mole of monoatomic ideal gas at T k under goes adiabetic change order under a constant external pressure of 1 atm changes volume from 1 litre to 2 litre. the final temperature in Kelvin would be?​

Answer 1

Answer:

Explanation:

T

​  

 

TV  

γ−1

=constant

Therefore,

T  

1

​  

V  

1

​  

 

γ−1

=T  

2

​  

V  

2

​  

 

γ−1

 

∵γ=  

3

5

​  

(∵the gas is monoatomic)

∴T  

1

​  

V  

1

​  

 

3

5

​  

−1

=T  

2

​  

V  

2

​  

 

3

5

​  

−1

 

⇒T  

1

​  

V  

1

​  

 

3

2

​  

 

=T  

2

​  

V  

2

​  

 

3

2

​  

 

 

Given that:-

V  

1

​  

=1L

V  

2

​  

=2L

T  

1

​  

=TK

∴T(1)  

3

2

​  

 

=T  

2

​  

(2)  

3

2

​  

 

 

⇒T  

2

​  

=  

2  

3

2

​  

 

 

T

​  

 

Hence the final temperature will be  

2  ^2/3

T

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