Question

when p=2,q=-4 andr=5find the value of (p-q-r)²,p²+q²+r²-2pq+2r-2rp​

Answer 1

Answer:

1.( p-q-r )^= (4 - 16 - 25 ),

2. ( p^ + q^ + r^ ) -2pq + 2r - 2rp = 2 - 16 + 25 + 16 - 16

Answer 2

Step-by-step explanation:

(p-q-r)^2[2-(-4)-5]^2 = [2+4-5]^2 = 1

p^2 + q^2 +r^2 - 2pq + 2r - 2rp=

(2)^2+(-4)^2+(5)^2-2×2×(-4)+2×5-2×5×2

4+16+25+16+10-20

31