*When p(x)=√3 then the value of polynomial x²-ax-5√3 is 3then finds the value of 'a'
1️⃣ -5
2️⃣ 5
3️⃣ 5√3
4️⃣ -5√3
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9
Answer:
Given −3 is the zero of the polynomial (k−1)x
2
+kx+1
So −3 must satisfy the equation (k−1)x
2
+kx+1=0
⟹(k−1)(−3)
2
+k(−3)+1=0
⟹9(k−1)−3k+1=0
⟹9k−9−3k+1=0
⟹6k=8
⟹k=
3
4
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0
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