Question

when p(x)=x^3-ax^2+x is divided by (x-a)

Answer 1

HOPE THIS ANSWER WILL HELP YOU Plz
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Answer 2

$heya \: mate \\ here \: is \: your \: answer \\ \\ x - a) {x}^{3} - {ax}^{2} + x( {x}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: {x}^{3} \: - {ax}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: - \: \: \: \: \: + \: \: \: \: \: \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x \\ \\ hope \: its \: helpful \: to \: you$

second method

x-a=0
x=a
then putting the value of x in the equation
we got,
x³-ax²+x
=(a)³-a(a)²+a
=a³-a³+a
subtracting that a³-a³
= a
a will be remaining as same above x is remaining
hope it's helpful to you