Question

when p(x) x^4+2x^3-3x+2-1 is divided by (x-2) what will the remainder???​

Answer 1

27 is answer.

I hope It will help you.

Answer 2

Answer:

Remainder = 21

Step-by-step explanation:

I guess you have some mistake in the question. Here is the corrected statement

We have been given the the expression:-

$x^{4} + 2x^{3} - 3x^{2} + x - 1$

We are required to find the remainder when it is divided by:-

$x - 2$

Let $x - 2 = 0$

$x = 2$

Substitute the value of 'x' in the expression:-

$p(2) = (2)^{4} + 2(2)^{3} - 3(2)^{2} + (2) - 1$

$p(2) = 16 + 2(8) - 3(4) + (2) - 1$

$p(2) = 16 + 16 - 12 + 2 - 1$

$p(2) = 21$

Therefore, when $x^{4} + 2x^{3} - 3x^{2} + x - 1$ is divided by $x - 2$ then the remainder is 21 !