Question

When p(x)=x²-8x+k leave same remainder (x-1) then the k=?

Answer 1

Answer:

p(1)=(1)^2-8(1)+k

2-8= k

k=-6

Answer 2

Answer:

$x - 1 = 0 \\ x = 1 \\ p(x) = x {}^{2} - 8x + k = 0 \\ 1 {}^{2} - 8 \times 1 + k \: = 0 \\ 1 - 8 + k = 0 \\ - 7 + k = 0 \\ k = 7$

K = 7

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