Question

When p(x) = x² - 8x +k, leaves a reminder when it is divided by x-1 then k=

Answer 1

$\huge\underline\mathbb\blue{ANSWER}$

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$\: \: \: \: \: \: \: \: x - 1 = 0 \\ => x = + 1$

$p(1) = {x}^{2} - 8x + k \\ p(1)= (1) - 8(1) + k \\ p(1) = 1 - 8 + k \\ p(1) = - 7 + k \\ + 7 \: \: = + k \\ k \: \: \: \: \: = 7$

hope it's helpful ✅✅✅