Question

when p(x)=x³+3x²+ax-13 is divided by x-3 the remainder is '-9'. find a​

Answer 1

Step-by-step explanation:

Now,

1. x-3)x^3+3x^2+ax-13(x^2+9x +(27–a)

x^3–3x^2

‐ +

______________

× +9x^2 +ax-13

+9x^2 –27x

– +

_______________

× +(27-a)x –13

+(27–a)x–3(27–a)

– +

___________________________

× +81–3a‐13

so,r= –9

now 81–3a-13=-9

68–3a=–9

3a=—9–68

a= –77÷3.