Business Studies, asked by yang920559, 10 months ago

When peaople smoke the nicotine they absorb is converted to cotinine which can be measured. A sample of 40 smokers has a mean contain level of 172.5 with standard deviation to be 119.5, use a 0.05 significance level to test the claim that the mean cotinine level of all smokers is more than 200.0?

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Answered by Anonymous
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However, so far we've just found point estimates, meaning we have just ... Xn have mean µ and standard deviation σ and either ... of 40 smokers has a mean cotinine level of 172.5.

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