Question

When perpendicular =1 and the base =root3 find the value of hypotenuse

Answer 1

Answer:

given :

p=1

base=$\sqrt{3}$

hypotenuse=$\sqrt{p^{2} +b^{2} }$

therefore,

h=$\sqrt{1^{2}+\sqrt{3} ^{2} }$

h=$\sqrt{1+3}$

h=$\sqrt{4}$

h=2.