Question

When Plz) = 8 25 + 3 z3 + 5 z+7 is divided by z+ 4.

Answer 1

Answer:

we have to solve the equation, 5(z + 3) = 4(2z + 1)

we know from algebraic identity,

k(a + b) = Ka + Kb

so, 5(z + 3) = 5z + 5 × 3

4(2z + 1) = 4 × 2z + 4

now, 5(z + 3) = 4(2z + 1)

or, 5z + 5 × 3 = 4 × 2z + 4

or, 5z + 15 = 8z + 4

or, 15 - 4 = 8z - 5z

or, 11 = 3z

or, 3z = 11

or, z = 11/3

hence, value of z = 11/3

verification : LHS = 5(z + 3)

= 5(11/3 + 3)

= 5[(11 + 3 × 3)/3 ]

= 5 × 20/3 = 100/3

RHS = 4(2z + 1)

= 4 (2 × 11/3 + 1)

= 4(22/3 + 1)

= 4(22 + 3)/3

= 4 × 25/3 = 100/3

here LHS = RHS

so, value of z = 11/3 is correct.

Step-by-step explanation: