When potassium iodide solution (ki) is added to another solution there is an yellow precipitate. Give the reaction, state the change.
Answers
Answer:
potassium iodide with lead nitrate{ Pb(NO3)2 } to form potassium nitrate and lead iodide.
lead iodide{PbI2} is precipitate.
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Answer:
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Explanation:
ANSWER
2KI(aq)+Pb(NO
3
)
2
(aq)→PbI
2
(s)+2KNO
3
In the above double displacement reaction, potassium Iodide(KI) and lead nitrate (Pb(NO
3
)
2
) dissociate in their aqueous states to form ions. The lead (Pb
2+
) ions combine with the iodide (I
−
) ions to form precipitates of lead iodide (PbI
2
). If Lead sulphate is used in place of lead nitrate, no precipitates of lead iodide will be formed, because lead sulphate being insoluble in water does not give Pb
2+
ions which can combine with I
−
to form PbI
2
. On the other hand, lead acetate dissociates in aqueous state to give Pb
2+
ions and CH
3
COO
−
ions . Therefore potassium iodide combines with lead acetate to form precipitates of lead iodide and potassium acetate.
2KI(aq)+Pb(CH
3
COO)
2
(aq)→PbI
2
(s)+2CH
3
COOK
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