when potassium iodine solution is
to a solution & lead nitrate in
test tube, a precipitate is formed.
balanced equvation
Answers
Answer:
Answer: a) yellow
b) Silver iodide
c) 2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)2KI(aq)+Pb(NO
3
)
2
(aq)→PbI
2
(s)+2KNO
3
(aq)
d) double displacement and precipitation
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+KNO_3(aq)KI(aq)+Pb(NO
3
)
2
(aq)→PbI
2
(s)+KNO
3
(aq)
The precipitates of PbI_2PbI
2
are yellow in colour and the chemical name for the precipitate is lead iodide.
The balanced chemical equation for this reaction is:
2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)2KI(aq)+Pb(NO
3
)
2
(aq)→PbI
2
(s)+2KNO
3
(aq)
The reaction is called as double displacement as exchange of ions take place and precipitation reaction as one of the product formed is solid in nature and do not solubilize in the solvent.