Chemistry, asked by sukhmaniA1422, 1 year ago

When potassium permanganate is titrated against ferrous ammonium sulphate the equivalent weight of potassium permanganate is?

Answers

Answered by vreddyv2003
49

Let's assume that Molecular Weight of Mohr's Salt is 'M'.

KMnO4 will oxidise Fe2+ ion to Fe3+ and will itself reduce to Mn2+

However, Fe2+ changes it's oxidation state by 1. Hence N-Factor or Valence Factor of Fe in Mohr's Salt is 1 and hence Equivalent Weight=Molecular Weight/N-Factor = M/1 = 1.

Instead of FeSO4, if someone asks you what's the n-factor of KMnO4, then it's answer is 5 and hence it's equivalent weight is one fifth of it's molecular weight.

Answered by rushirajesh8
5

Answer:

m/5

Explanation:

molecular weight of Mohr's salt is M

kmno4 will oxidise into fe2+ ion into fe3+

and will reduce itself into mn2+

fe2+ oxidation

equivalent wt = molecular wt / n factor

m/1=1

n factor of kmno4 is 5 hence

Answer : m/5

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