Question

When Pressure is expressed in atmospheres and volume in litres. One mole of gas

under S.T.P. Conditions (at 273 K and 1 atmosphere pressure) occupies 22.4L, then

value of R​

Answer 1

Answer:

0.082057 L atm or 0.083 (for ease in calculations)

Explanation:

Use the formula PV = nRT

make R, the subject of equation -> $R= \frac{PV}{nT}$

Substitute the values and solve it.

Answer 2

The value of R is 0.0821Latm/Kmol

Explanation:

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 1 atm    (STP)

V= Volume of the gas = 22.4 L

T= Temperature of the gas =  273 K (STP)

R= Gas constant = ?

n= moles of gas   = 1

$R=\frac{PV}{nT}=\frac{1atm\times 22.4L}{1mol\times 273K}$

$R=0.0821Latm/Kmol$

Thus the value of R is 0.0821Latm/Kmol

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