When Pressure is expressed in atmospheres and volume in litres. One mole of gas under S.T.P. Conditions (at 273 K and 1 atmosphere pressure) occupies 22.4L, then value of R is
1) 1.0821 L atm k -1 mol-1
(2) 0.0821 L atm k -1 mol -1
(3) 2.0821 L atm k -1 mol-1
(4) None of these
Answers
Answered by
2
0.0821 L atm-1 mil -1
hope it will help you
Answered by
4
Given:
Pressure, P = 1 atm
Volume, V = 22.4 litre
No. of moles, n = 1 mole
Temperature, T = 273 K
To Find:
Universal Gas Constant, i.e., R
Calculation:
- Putting all these values in Ideal Gas Equation, we get:
PV = nRT
⇒ 1 × 22.4 = 1 × R × 273
⇒ R = 22.4/273
⇒ R = 0.0821 L atm K⁻¹ mol⁻¹
- So the correct answer is option (2)
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