When propanone is reduced with NaBH, the alcohol formed
a) Primary
b) Secondary
c)
Tertiary
ii)
d) All
The tertiary alcohol can be obtained by hydration of:
a) 2-methyl prop-1-ene
b) Propene
c)
But-1-ene
d)
but-2-ene
Answers
Explanation:
1.
When propanone is reduced with NaBH₄, the alcohol formed
a) Primary
b) Secondary ✔
c) Tertiary
d) All
Explanation:
O OH
|| |
CH₃—C—CH₃ + NaBH₄ → CH₃—C—CH₃
|
H
(2° Alcohol)
2.
The tertiary alcohol can be obtained by hydration of
a) 2-methyl prop-1-ene ✔
b) propene
c) but-1-ene
d) but-2-ene
Explanation:
- 3° Alcohol -
R
|
R—C—OH
|
R
Here, we have to check all options :-
a)
CH₃ CH₃
| |
CH₃—C=CH₂ + H₂O → CH₃—C—CH₃
|
OH
(3° Alcohol)
Here, Option A gives tertiary alcohol by hydration.
So,
Option A is correct.