Chemistry, asked by bablifahim7, 6 months ago

When propanone is reduced with NaBH, the alcohol formed
a) Primary
b) Secondary
c)
Tertiary
ii)
d) All
The tertiary alcohol can be obtained by hydration of:
a) 2-methyl prop-1-ene
b) Propene
c)
But-1-ene
d)
but-2-ene​

Answers

Answered by TrickYwriTer
23

Explanation:

1.

When propanone is reduced with NaBH₄, the alcohol formed

a) Primary

b) Secondary ✔

c) Tertiary

d) All

Explanation:

O OH

|| |

CH₃—C—CH₃ + NaBH₄ → CH₃—C—CH₃

|

H

(2° Alcohol)

2.

The tertiary alcohol can be obtained by hydration of

a) 2-methyl prop-1-ene ✔

b) propene

c) but-1-ene

d) but-2-ene

Explanation:

  • 3° Alcohol -

R

|

R—C—OH

|

R

Here, we have to check all options :-

a)

CH₃ CH₃

| |

CH₃—C=CH₂ + H₂O → CH₃—C—CH₃

|

OH

(3° Alcohol)

Here, Option A gives tertiary alcohol by hydration.

So,

Option A is correct.


BrainlyIAS: Tricky Answer :-) ❤ Nice :)
Similar questions