Question

When put a balloon in a warm oven, the temperature goes from 70o to 140o. Will the 200 ml balloon shrink or expand? What will the new volume of the balloon be?

Answer 1

Answer: -

According to Charles Law,

The volume of a gas is directly proportional to the absolute temperature. Thus as the temperature of the balloon is increased from 70 °C to 140 °C, the volume of the balloon will increase and the balloon will therefore expand.

Initial volume = 200 mL

Initial temperature = 70+273 = 343 K

Final temperature T 2 = 140+273 = 413 K

According to the formula

$\frac{V1}{T1}$ = $\frac{V2}{T2}$

$\frac{200 mL}{343 K}$ = $\frac{V2}{413 K}$

V 2 = $\frac{200 mL x 413 K}{343 K}$

    = 240.81 mL

Thus the new volume of the balloon is 240.81 mL.