Math, asked by saritadipakmahale, 7 months ago

When Ravina read-3/4th part and 17 pages of a Marathi book, 28 pages were left to
be read. When Kajal read -3/5th part and 20 pages of a History book, 26 pages were
left to be read. How many more pages were there in Ravina's book than the
number of pages in the book that Kajal had?
(1) 65
(2) 75
(3) 55
(4) 45​

Answers

Answered by antarasartale11
11

Answer:

1) 65

Step-by-step explanation:

Let the total number of pages in Ravina's book be x

She read - 1) 3/4th part of the book 2) 17 pages and 26 pages were left

therefore, (3/4x × 17) + 28 = x

therefore, x - 3x/4 = 45

therefore, x/4 = 45

therefore, x = 45 × 4 = 180

Now, let the number of pages in Kajal's book be x

She read - 3/5th part of the book 2) 20 pages and 26 pages were left

therefore, (3/5x + 20) + 26 = x

therefore, x - 3/5x = 46

therefore, 2/5x = 46

therefore, 2x/5 = 46

therefore, 2x = 46 × 5 = 230

therefore, x = 230/2 = 115

so, 180 - 115 = 65

Answer - There are 65 pages more in the Ravina's book than the number of pages in the book that Kajal had.

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