when ravina read 3/4th part and 17 pages of a marathi book ,28 pages were left to be read .when kajal read 3/5th part and 20 pages of a history book,26 pages were left to be read.how many more pages were there in ravinas book than the number of pages in the book that kajal had ?
Answers
Answer:
Ravina book has 65 pages more than Kajal book.
Step-by-step explanation:
Let us assume Ravina book has X pages and Kajal book has Y pages.
Ravina read 3/4th of book and 17 pages. There are 28 pages left.
i.e 3X/4 + 17 = X – 28
3X = 4(X – 28 – 17) = 4(X – 45) = 4X – 180.
X = 180.
Ravina book has 180 pages.
Kajal read 3/5th of book and 20 pages. There are 26 pages left.
i.e. 3Y/5 + 20 = Y – 26
3Y = 5(Y – 26 – 20) = 5(Y – 46) = 5Y – 230
2Y = 230
Y = 230/2 = 115.
Kajal book has 115 pages.
Ravina book has 180 – 115 = 65 pages more than Kajal book.
Answer:
Step-by-step explanation:
Ravina=3/4,17 pages,28 pages
Kajal=3/5,20 pages,26 pages
1-3/4=1/4
1/4=17+28
1/4=45
4/1×45=180 pages
1-3/5=2/5
2/5=20+26
2/5=46
5/2×46=115 pages
Difference=180-115=65.