Question

when Resistance 60 ohms and 90 ohms are connected in parallel .how to calculate equivalent resistance?​

Answer 1

Answer:

equivalent resistance is 36 ohm

Explanation:

equivalent resistance in parallel=

Req= R1×R2/R1+R2

Req= 60×90/150=36 ohm

Answer 2

Given:-

• Resistors of resistance of 60 ohms and 90 ohms are connected in parallel.

To Find:-

• What is the equivalent resistance?

Solution :-

• Let Rp be the equivalent resistance.

Here we have:-

• $\sf R_1 = 60 ohms$
• $\sf R2 = 90 ohms$

ㅤㅤㅤㅤ$\small {\mathfrak {\underline { We \: know \: that \: :- }}}$

$\sf\red{ {\dfrac {1}{R_p} = \dfrac {1}{R_1} + \dfrac {1}{R_2} + \dfrac {1}{R_3} +.. }}$

$\small\underline{\pmb{\sf \:Substituting \: Values :-}}$

$\sf \: \: \: \: \: \: \:\: \: :\implies \dfrac{1}{R_p} = \dfrac{1}{60} + \dfrac{1}{90}$

$\sf \: \: \: \: \: \: \:\: \: :\implies\dfrac{1}{R_p} = \dfrac{3+2}{180}$

$\sf \: \: \: \: \: \: \:\: \: :\implies \dfrac{1}{R_p} = \dfrac{5}{180}$

$\sf \: \: \: \: \: \: \:\: \: :\implies \dfrac{1}{R_p }= \dfrac{1}{36}$

$\sf \: \: \: \: \: \: \:\: \: \red{:\implies R_p = 36Ω}$

$\therefore\:\underline{\textsf{ The equivalent resistance is \:\textbf{36Ω}}}.$