When resistor R is connected to a battery of 3 V , it draws a current of 1 ampere , find the value of R. if an identical resistor is connected in parallel with it find the current that flow through he circuit.
Answers
Answered by
60
Given : 2 Identital resistors in Parallel.
Votage = 3V
Current = 1 Amp ⇒ R = 3 Ohms
Effective Resistance (R') = (R1R2) / (R1 + R2) = R²/2R = R/2 ⇒ 1.5Ohms
I = V/R = 3/1.5 = 2 Amps
Current Flowing = 2 Amps
Votage = 3V
Current = 1 Amp ⇒ R = 3 Ohms
Effective Resistance (R') = (R1R2) / (R1 + R2) = R²/2R = R/2 ⇒ 1.5Ohms
I = V/R = 3/1.5 = 2 Amps
Current Flowing = 2 Amps
Answered by
43
R=V/I
R=3V/1A
R=3 Ohm
so now the identical resistor are connected in parralel
1/R3= 1/R1+1/R2
1/R3=2/3
R3=3/2
NOW
R3=V/I
3/2=3/I
2 A = I
SO CURRENT OF 2A WILL FLOW IN THE CIRCUIT
HOPE YOU LKE IT
R=3V/1A
R=3 Ohm
so now the identical resistor are connected in parralel
1/R3= 1/R1+1/R2
1/R3=2/3
R3=3/2
NOW
R3=V/I
3/2=3/I
2 A = I
SO CURRENT OF 2A WILL FLOW IN THE CIRCUIT
HOPE YOU LKE IT
Similar questions