When rolling a fair number cube that is numbered 1–6, which event is impossible?
A.rolling an odd number
B.rolling an even number
C.rolling a number less than 7
D.rolling a number greater than 6
Answers
Answered by
1
Answer:
d part
Step-by-step explanation:
bcz if no. is between 1-6 then how greater than 6 can come
Answered by
1
Answer: (D) The event that is imposbbile is obviously rolling a numebr greater than 6
Using common sense : - You cant get a number greater 6 as 6 is the most you can get while rolling die (cube here)
Using math's : - Sample space (S) = total outcomes = [1,2,3,4,5,6]
P (rolling an odd number) = n(favorable)/n(S) = 3/6 = 1/2
P (rolling an even number) = 3/6 = 1/2
P (rolling number less than 7) = 6/6 = 1
P (rolling number greater than 6) = 0/6 = 0
Since an impossible event has a probability as O
Therefore your Ans is (d)
Similar questions