Math, asked by sarchjones, 3 months ago

When rolling a fair number cube that is numbered 1–6, which event is impossible?

A.rolling an odd number

B.rolling an even number

C.rolling a number less than 7

D.rolling a number greater than 6

Answers

Answered by amm0
1

Answer:

d part

Step-by-step explanation:

bcz if no. is between 1-6 then how greater than 6 can come

Answered by mfb8525
1

Answer: (D) The event that is imposbbile is obviously rolling a numebr greater than 6

Using common sense : - You cant get a number greater 6 as 6 is the most you can get while rolling  die (cube here)

Using math's : - Sample space (S) = total outcomes  = [1,2,3,4,5,6]

P (rolling an odd number) = n(favorable)/n(S) =  3/6 = 1/2

P (rolling an even number) = 3/6 = 1/2

P (rolling number less than 7) = 6/6 = 1

P (rolling number greater than 6) = 0/6 = 0

Since an impossible event has a probability as O

Therefore your Ans is (d)

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