when root3x^3-5x(x-root2)-root6(x^2+2)+2root3(x+2)is divided by (x-root2)
Answers
Answered by
1
Answer
Open in answr app
3x2 − 22x − 23 = 0
Multiplying the equation throughout by 3,
3x2 − 2×3×2×x − 6 = 0
(3x)2 − 2×3x×2 + (2)2 − (2)2 − 6 = 0
(3x−2)2 − 2 − 6 = 0
(
Answered by
0
Answer:
The answer for this sum is 0//
Similar questions