Question

when secA13/12 find the sinA=?​

Answer 1

$\huge\underline\mathtt\pink{Solution}$

$\sec \: A = \frac{13}{12} = \frac{hyp}{adj} \\ \\ {hyp}^{2} = {opp}^{2} + {adj}^{2} \\ {13}^{2} = {opp}^{2} + {12}^{2} \\ 169 = {opp}^{2} + 144 \\ {opp}^{2} = 169 - 144 \\ {opp}^{2} = 25 \\ opp = \sqrt{25} \\ opp = 5cm$

$sin \: A \: = \frac{opp}{hyp} \\ \\ sin \: A \: = \frac{5}{13}$

Answer 2

Answer:

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