Question

when should be added to 6 x ka power 5 plus 4 ka power 4 minus 27 Essar power minus 7 x power 2 - 27 x minus 6 so that the resulting polynomial is exactly divisible by 2 X ka power 2 - 3​

Answer 1

Step-by-step explanation:

6*5 =30

4-27=23

27-2=25

30+23+25=78