Question

When shunted ,the current sensitivity of a galvanometer reduces by a factor of 100.the resistance of the shunt is

Answer 1

It is a conversion of galvanometer into ammeter . When a small resistance i.e. shunt resistance is connected in parallel of galvanometer it's current efficiency decreases .

Shunt resistance can be calculated as RS= ( Ig/I-Ig)Rs

Answer 2

The resistance of shut becomes 1/99 of the galvanometer resistance.

Explanation:

The Shunt resistance of galvanometer is given as

$S = \frac{GI_g}{I-I_g}$

Here, G is the galvanometer resistance and Ig current through galvanometer.

Given, $I=100I_g$.

Substitute the value, we get

$S=\frac{GI_g}{100I_g-I_g}$

$S=\frac{G}{99}$

Thus, the resistance of shut becomes 1/99 of the galvanometer resistance.

#Learn More: Shut resistance

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