Question

when sides of a square are increased by 6cm each,it's area becomes 1225cm square.Find the sides of both squares​

Answer 1

GIVEN :-

• If the sides of a square are increased by 6 cm each, it's area

        becomes 1225 cm² .

TO FIND :-

• Sides of both squares.

SOLUTION :-

Let,

Side of first square = x

Side of second square = x + 6

$\longrightarrow \sf (x+6)^2= 1225 \\\\\longrightarrow x^2+(2\times 6\times x)+6^2= 1225 \\\\\longrightarrow x^2+12x+36 = 1225 \\\\\longrightarrow x^2+12x = 1225-36 \\\\\longrightarrow x^2+12x = 1189 \\\\\longrightarrow x^2-12x-1189 = 0 \\\\\longrightarrow x^2-29x+49x- 1189 = 0 \\\\\longrightarrow x(x-29)+49(x-29) = 0 \\\\\longrightarrow (x-29)(x+49)= 0 \\\\\longrightarrow \bf x = 29 \ , \ x =- 49$

Side of a square cannot be negative.

Side of the first square = 29 cm

Side of the second square = 29 + 6

                                              = 35 cm

Answer 2

let the

side of first square is x

then

side of second square is x+6

Area of seccond square (x+6)² = 1225

(x+6) = √1225

x+6= 35

x= 35-6

x= 29

hence the side of first square is 29

and second square is 36