Chemistry, asked by evasidhani6334, 1 month ago

When silver acetate is treated with bromine in presence of ccl4 the product is

Answers

Answered by 7dshanchitajaneciyas
0

Answer:

In this second propagation step, an alkyl bromide - the product - is formed and a carboxyl radical is recovered. ➡️The Hunsdiecker reaction takes place when a silver carboxylate is heated in CCl4 in the presence of bromine. ... This yields a carboxyl radical and a bromine atom.

Explanation:

Mark as Brainliest❣️ (Φ ᆺ Φ)

Similar questions