Question

When simplify, {(2/3)^2}^3×(1/3)^-4 × (3)^-1×(1/6)​

Answer 1

Step-by-step explanation:

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Answer 2

$[\{(\frac{2}{3})^2\}^3\times (\frac{1}{3})^{-4}\times 3^{-1}\times (\frac{1}{6})]$

$=[\{(\frac{4}{9})\}^3\times (3)^{4}\times\frac{1}{3} \times (\frac{1}{6})]$

$=[\frac{64}{729}\times 81\times\frac{1}{3} \times \frac{1}{6}]$

$=\frac{32}{81}$