Question

When SinA+SinB=2 then sin(A+B)

Answer 1

Answer:

sin(A+B)=0

Step-by-step explanation:

There is only possibility if sinA+ sinB =2

A=B =90°

so, sin90 +sin90 =2

1+ 1=2

therefore

sin (A+B)

= sin(90°+90°)

= sin180°

= 0

sin(A+B)=0

Hope this helps you

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Answer 2

sinA=1

A=n(π/2) where n is odd

and

B=n(π/2)

A+B=(m+n)(π/2)

where m,n are odd

A+B= k(π/2) and k is even .( as the sum of two odd numbers is even )

hence

sin (A+B) =0