Question

When sodium sulphate reacts with barium chloride solution state the observation and give the chemical reaction involved?

Answer 1

$\bold{SODIUM \: SULPHATE}$

Sodium is a alkali metal which lies in group 1 and peroid 3 of Modern periodic table, so by convey it has one valence electron +1..So to be stable like nearest noble gas it will lose its one electron.

Sulphate radical has valance -2 .

When the both reacts , since valency of sulphate ion is -2 ,so two sodium ion will be needed.

$\bold{Na_2SO_4}$

$\bold{BARIUM \: CHLORIDE}$

Barium lies in group 2 of modern periodic table so its valency is +2.So to be stable like nearest noble gas it will lose its two electrons.

Chloride radical have valency -1.

When barium reacts with chloride, since the valency of barium is +2 , two chloride ion will be needed.

$\bold{BaCl_2}$

$\huge \bold{ Na_2SO_4+ BaCl_2}$

When sodium sulphate reacts with barium chloride it by double displacement reaction forms a white precipitate of barium sulphate and salt sodium chloride.

$\bold{EQUATION}$

$\bold{ Na_2SO_4+ BaCl_2 \longrightarrow 2NaCl + BaSO_4}$

$\bold{ Test \: to \: check \: sulphate \: radical }$

When hydrochloric acid is added to barium sulphate, a the white precipitate of barium sulphate dissolves .If it would have been sulphite it would have not got dissolved.

Answer 2

Answer:

A white ppt. ( precipitate ) is formed.

Na₂SO₄ ( aq ) + BaCl₂ ( ag ) ⇒  2 NaCl ( aq ) + BaSO₄ ( ↓ )

Doubled Displacement reaction

The reaction in which there is an exchange of ions between the reactants.