Question

when Sourav increases his speed from 20 km per hour to 25 km per hour he takes 1 hour less than the usual time to cover a certain distance what is the distance usually covered by him​

Answer 1

let initial speed be s and final be a

let distance be x , let time b t for s & t" for a

case 1 : s = 20 kmph

s=d/t => t = x /20

case 2 : s = 25 kmph

s=d/t => t" = x/25

now ,

t" = t - 1 => x/25 = x /20- 1 => x/25 - x /20= - 1

=> x/5 (-1/20) = -1 => x/5 (-1/20) = -1 => x = 100

•°• x = 100 km....hope it helps !!¿

Answer 2

Answer:

100km

Step-by-step explanation:

Let the distance covered by saurabh =x

Time diffence from 20 kmh to 25 kmh

=(x/20-x/25)=1

5x-4x=100

x=100

So distance covered=100 km