When spring elongates by 10cm energy stored in it is 500J. Calculate force constant of spring.
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1/2kx^2 =500
x =0.1m
putting the value of x we get k= 100000
force = kx. =100000*0.1=10000N
x =0.1m
putting the value of x we get k= 100000
force = kx. =100000*0.1=10000N
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