Question

when sugar is 10 kgs a cent. a sum of money maintain a family of 18 men for 15 days.how long will the same amount of money maintain a family of 6 men when sugar is 14 kgs a cent


57 days
63 days
67 days
53 days​

Answer 1

Answer:

b is the correct answer

Step-by-step explanation:

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Answer 2

The same amount of money can maintain a family of 6 men for 21 days when sugar is 14 kgs a cent. therefore option d) 53 days correct.

Let's begin by finding out how much money is required to maintain a family of 18 men for 15 days when sugar is 10 kgs a cent.

Cost of 1 kg of sugar = 1/10 cent

Cost of sugar required for 1 man for 1 day = 1/10 kg * 1/18 cent = 1/180 cent

Cost of sugar required for 1 man for 15 days = 1/180 cent * 15 = 1/12 cent

Cost of sugar required for 18 men for 15 days = 18 * 1/12 cent = 3/2 cent

So, it takes 3/2 cent to maintain a family of 18 men for 15 days when sugar is 10 kgs a cent.

Now, we need to find out how long the same amount of money can maintain a family of 6 men when sugar is 14 kgs a cent.

Cost of 1 kg of sugar = 1/14 cent

Cost of sugar required for 1 man for 1 day = 1/14 kg * 1/6 cent = 1/84 cent

Cost of sugar required for 1 man for x days = 1/84 cent * x

Cost of sugar required for 6 men for x days = 6 * 1/84 cent * x = x/14 cent

We know that the cost of maintaining the family of 18 men for 15 days is 3/2 cent, and we need to find out how long the same amount of money can maintain a family of 6 men when sugar is 14 kgs a cent.

3/2 cent = x/14 cent

x = (3/2) * 14 / 1

x = 21

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