When sulphur dioxide is passed in an acidified K2Cr2O7 solution,from which range does the oxidation state of sulphur change?
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Reaction of sulphur dioxide with K2Cr2O7in acidic medium is given as
3 SO2 + Cr2O72- + 2 H+ →3 SO42- + 2 Cr3++ H2O
Oxidation state of Sulphur in SO2 is+4 which changes to +6 in SO42-
3 SO2 + Cr2O72- + 2 H+ →3 SO42- + 2 Cr3++ H2O
Oxidation state of Sulphur in SO2 is+4 which changes to +6 in SO42-
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