Question

When sulphur dioxide is passed through an acidified k2cr2o7 solution, the oxidation state of sulphur changes from

Answer 1

Answer:

+4 to +6

Explanation:

the rxn acc to the generalisation is

Cr2O7^(-2) + 14H^(+1) + 6e- 》》2Cr^(+3) + 7H2O

Is

K2Cr2O7 + 3SO2+ H2SO4》》Cr2(SO4)3 + K2SO4 + H2O

Here we see that SO2 is changed to SO4^(-2)

Which have +4&+6 Oxidation states respectively