Question

When sulphur is burnt in oxygen it forms sulphur dioxide. Calculate the heat given out when 1.6 g of sulphur is burnt.
 
S + O2 ® SO2 energy change = -297 kJ/mol
 

Answer 1

Answer:

S + O2 → SO2

S + O2 → SO2here we see 1 mole of sulphur react with 1 mole of Oxygen and form 1 mole of SO2 .

S + O2 → SO2here we see 1 mole of sulphur react with 1 mole of Oxygen and form 1 mole of SO2 .so, 32g of S react 32 of O2 and form 64 g of SO2

S + O2 → SO2here we see 1 mole of sulphur react with 1 mole of Oxygen and form 1 mole of SO2 .so, 32g of S react 32 of O2 and form 64 g of SO2so, 1 g of S react with 1 g of O2 and form 2g of SO2

S + O2 → SO2here we see 1 mole of sulphur react with 1 mole of Oxygen and form 1 mole of SO2 .so, 32g of S react 32 of O2 and form 64 g of SO2so, 1 g of S react with 1 g of O2 and form 2g of SO2so, 10g of S react with 10g of 10g of O2 and form 20g of SO2 .

S + O2 → SO2here we see 1 mole of sulphur react with 1 mole of Oxygen and form 1 mole of SO2 .so, 32g of S react 32 of O2 and form 64 g of SO2so, 1 g of S react with 1 g of O2 and form 2g of SO2so, 10g of S react with 10g of 10g of O2 and form 20g of SO2 .hence, statement is correct !!!!

Answer 2

Enthalpy of combustion of sulphur = -297 KJ/mol

Molar mass of sulphur = 32g

No. of moles of 1.6 g sulphur = 1.6/32 = 0.05 moles.

Enthalpy of reaction for 0.05 moles sulphur = 0.05 * -297 = -14.8 KJ/mol