when sulpur is heated with Sodium Hydroxide compound formed is
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Sulfur reacts with sodium hydroxide in the following way:
3S+6NaOH⟶2Na2S+Na2SO3+3H2O3S+6NaOH⟶2NaX2S+NaX2SOX3+3HX2O
It is a disproportionation reaction: sulfur's oxidation changes from zero to -2 in sodium sulfide and from zero to +4 in sodium sulfite.
3S+6NaOH⟶2Na2S+Na2SO3+3H2O3S+6NaOH⟶2NaX2S+NaX2SOX3+3HX2O
It is a disproportionation reaction: sulfur's oxidation changes from zero to -2 in sodium sulfide and from zero to +4 in sodium sulfite.
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8NAOH + 4S = Na2S2O3 +2 Na2S + 3 H2O
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