Math, asked by dashappy78, 1 year ago

When Sunita weighed herself on Monday she had guined 5\4 earlier her weight was 371/8 kg what was her weight on Monday

Answers

Answered by bhagyashreechowdhury
2

Given:

When Sunita weighed herself on Monday she had gained 5\4 earlier her weight was 371/8 kg

To find:

What was her weight on Monday

Solution:

Earlier Sunita's weight was = 37\frac{1}{8} \:kg = \frac{296 +1}{8} = \frac{297}{8}\:kg

After weighing herself on Monday, she noticed that she has gained \frac{5}{4} \: kg

∴ Sunita's weight on Monday was,

= [Previous weight] + [Weight gained on Monday]

= \frac{297}{8} + \frac{5}{4}

= \frac{297 \:+\:10}{8}

= \frac{307}{8} \:kg

converting the fraction into a mixed fraction by using a long division method

= \bold{38\frac{3}{8} \:kg}

Thus, Sunita's weight on Monday was \underline{38\frac{3}{8}\:kg }.

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