Question

When temperature of a gas contained in a closed vessel is increased by 5 degree Celsius its pressure increases by1% .the original temperature of the gas was approximately?

Answer 1

Formula for dependence of pressure P of a gas in an enclosure at an absolute temperature T:

P = k T

Where k is a constant.

So relative increases :

delta P / P = delta T / T

Substituting given data values we get

1% = 5° / T

T = 500° Kelvin abs temp

Answer 2

Explanation:

temperature is 500°kelvin

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