Question

when term of the Series 79,77,75...is 47

Answer 1

Which term of the series 79,77,75___ is 47.
find out the a%5Bn%5D
as you can see, the differences between each pair of numbers are always 2, each next term is 2 less then previous one
a+=+79 (the first term)
d+=+2 (the "common difference" between terms)
And we get:
{ a, a-d, a-2d, a-3d, ... }
We can write an arithmetic sequence as a rule:
a%5Bn%5D+=+a+-+d%28n-1%29
(We use "n-1" because d+is not used in the 1st term).
check the formula:
a%5B1%5D+=79+-+2%281-1%29=79


a%5B2%5D+=79+-+2%282-1%29=79+-+2%281%29=79-2=77
a%5B3%5D+=79+-+2%283-1%29=79+-+2%282%29=79-4=75
calculate which term is equal to 47:
47=+79+-+2%28n-1%29
47=+79+-+2n%2B2
47=+81+-+2n
2n=+81+-+47
2n=+34
n=+34%2F2
n=+17
so, 47 is 17th term

HOPE IT WILL WORK

Answer 2

since the common difference in this is -2
47=79+(n-1)*-2
=> 47=79+2n-2
-30=2n
n=-15
Hence, the sixteenth term of this series is 47
please mark it brainliest