when the angle of elevation of sun changes from 45° to 60°. The length of the shadow of a tower changes to 4 metre. What is the height of the tower.
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Answer:
In ΔTOW,
tan45
o
=
x
h
∴x=h
In ΔT×w,
tan30
o
=
60+x
h
3
1
=
60+h
h
60+h=
3
h
60=h(
3
−1)
h=
3
−1
60
=
3−1
60(
3
+1)
=30(
3
+1)m
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