Question

When the area of shoe sale is l0 cm² & A boy of mas 50 kg is wearing them Calculate pressure develop by boy on ground when
1. He is standing on both fets
2.He is standing on one feet only.​

Answer 1

Given :

• Mass of the boy = 50 kg
• Area of a shoe sole = 10 cm² .

To find :

⇢ Pressure when

• He is standing on both feets
• He is standing on one feet only

Conversions :

⇢ Area of the shoe sole = 10 cm²

$\tt = 10 \times {10}^{ - 4} \: {m}^{2}$

$\tt = {10}^{ - 3} {m}^{2}$

Solution :

The formula of pressure is given by

$\boxed{\sf{Pressure = {\dfrac{Force}{Area}}}}$

Force = mg

= 50× 9.8

= 490

1) When he is standing in both shoes

Area of two shoes = 2 × Area of one shoe sole

$\tt = 2 \times {10}^{ - 3} \: {m}^{2}$

Pressure when he is standing on both shoes =$\tt{\dfrac{490}{2 \times 10^{-3}}}$

= 245 × 10³ Pa

= 2.45 × 10⁵ Pa

2) Pressure when he is standing on one feet = $\tt{\dfrac{490}{10^{-3}}}$

= 490 × 10³ Pa

= 4.9 × 10⁵ Pa