Question

When the axes are rotated through an angle
$\alpha \:$
, find the transformed equation of x cos
$\alpha$
+ y sin
$\alpha$
=p​

Answer 1

Ans.

By rotation of axes,

By rotation of axes,x=x

By rotation of axes,x=x 1

By rotation of axes,x=x 1

By rotation of axes,x=x 1 cosα−y

By rotation of axes,x=x 1 cosα−y 1

By rotation of axes,x=x 1 cosα−y 1

By rotation of axes,x=x 1 cosα−y 1 sinα

By rotation of axes,x=x 1 cosα−y 1 sinαy=x

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosα

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2 α+sin

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2 α+sin 2

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2 α+sin 2 α)+y(sinαcosα−cosαsinα)=P..............(substitute the values of x and y)

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2 α+sin 2 α)+y(sinαcosα−cosαsinα)=P..............(substitute the values of x and y) x

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2 α+sin 2 α)+y(sinαcosα−cosαsinα)=P..............(substitute the values of x and y) x 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2 α+sin 2 α)+y(sinαcosα−cosαsinα)=P..............(substitute the values of x and y) x 1

By rotation of axes,x=x 1 cosα−y 1 sinαy=x 1 sinα+y 1 cosαxcosα+ysinα=P..........(given)⇒x 1 (cos 2 α+sin 2 α)+y(sinαcosα−cosαsinα)=P..............(substitute the values of x and y) x 1 =P => X=P.

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Answer 2

Step-by-step explanation:

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