Question

When the block lies on its side of
dimensions 40 cm x 20 cm, it exerts
the same thrust.
Area= length x breadth
40 cm x 20 cm
800 cm2 = 0.08 m2
From Eq. (10.20),
49N
Pressure =
0.08 m2
= 612.5 N m-2
The pressure exerted by the side 20 cm
x 10 cm is 2450 N m2 and by the side
40 cm x 20 cm is 612.5 N m-2.​

Answer 1

Answer:

dimensions 40 cm x 20 cm, it exerts

the same thrust.

Area= length x breadth

40 cm x 20 cm

800 cm2 = 0.08 m2

From Eq. (10.20),

49N

Pressure =

0.08 m2

= 612.5 N m-2

The pressure exerted by the side 20 cm

x 10 cm is 2450 N m2 and by the side

40 cm x 20 cm is 612.5 N m-2.​

Answer 2

Answer:

The mass of the wooden block = 5 kg

The dimensions = 40 cm x 20 cm x 10 cm

Here, the weight of the wooden block applies a thrust on the table top.

That is,

Thrust = F (force) = m x g

                               = 5 kg x 9.8 m s^-2

                               = 49 N (newton)

Area of a side =  length x breadth

                        = 20 cm x 10 cm

                        = 200 cm^2  = 0.02

From Eq. (10.20),

Pressure = 49 N / 0.02 m^2

                = 2450 N m^-2.

When the block lies on its side of dimensions 40 cm x 20 cm, it exerts the same thrust.

Area = length x breadth

        = 40 cm x 20 cm

        = 800 cm^2 = 0.08 m^2

From Eq. (10.20),  

Pressure = 49 N / 0.08 m^2

                = 612.5 N m^-2

The pressure exerted by the side 20 cm x 10 cm is 2450 N m^-2 and by the side 40 cm x 20 cm is 612.5 N m^-2.