Question

When the bob of a simple pendulum of length ‘l’ is released from its horizontal position, it strikes a
block of equal mass (m) lying on a frictionless table as shown in the figure. The bob transfers all its
momentum to the block. The kinetic energy of the block will be (g = acceleration due to gravity at the
place)

Answer 1

Answer:

Using the principle of conservation of mechanical energy, determine the speed of the block with a mass of 2.00kg as the block of mass 6.00kg hits the ground. the 6.00kg object is initially positioned at 2.00m high from the ground. consider frictionless pulley and neglect air resistance. show your solution.