When the breaks applied to a car produces an acceleration of 6 metre per second square in the opposite direction to the motion. If a car takes 2 seconds to stop after the application of break. Calculate the distance travelled by during this time?
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The brakes applied to a car produce an acceleration of 6ms^-2 in the opposite direction to the motion. If the car takes 2 s to stop after the application ...
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Given:Accerleration: a = - 6 m/s^2 Time t = 2 s Final velocity, v = 0 m/s v = u + at 0 = u - 6 × 2 u = 12 m/s s = ut + 12at^2 s = 12 × 2 + 12 × ( - 6) ... More
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